How do you solve #abs(x-1)+17=6#?

1 Answer
Apr 2, 2015

There is no value of #x# to satisfy this equation.

#abs(x-1) = -11#

As we know, absolute value will always return a non-negative value.

Such that:

#if c >= 0, abs(c) = c#

#if c < 0, abs(c) = -c#

So either way the right-hand part of the equation where the absolute value is equal to is always be positive (or zero).

Since #-11# is a negative number, there is no such #x# to satisfy the equation because absolute value will never be equal to a negative number.

The result is: #x in {}#