How do you solve #2abs(3-x)+10=5#?

1 Answer
Apr 3, 2015

The answer is: #x in {}#

If there is only one absolute value operator, leave it alone at a side of the equation first. That makes easier to solve them.

#2abs(3-x)=-5#

#abs(3-x) = -5/2#

Now we can see that there is no such value of #x# to solve this equation since the absolute value operator returns only non-negative.

The result is: #x in {}#