Question

How do you solve for m in `m/6 = 1/3`?

Answer 1

In general if
`a=b`
then
`k*a = k*b`

That means we can multiply both sides of an equation by a constant and the equation will still be true.

Multiply both sides of `m/6 = 1/3` by `6`
`cancel(6)*m/cancel(6) = 6*1/3 = 2`

`m = 2`