Question

How do you simplify `(w^21w^-12)/w^9`?

Answer 1

General rules that you should know:
`b^p * b^q = b^(p+q)`
and
`(b^r)/(b^s) = b^(r-s)`
and
`b^0 = 1`

So `(w^21*w^(-12))/(w^9)`

`= w^ (21+(-12) -9)`

`= w^0`

#=1