What is the derivative of #sqrt(x^5)#?

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Answer 1 · 2015-04-12T03:20:34

Write it as: #x^(5/2)# and the derive it as #x^n# (giving #nx^(n-1)#):
#y'=5/2x^(5/2-1)=5/2x^(3/2)=5/2sqrt(x^3)#