How do you find the derivative of the function # y = tan^4(3x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Apr 12, 2015 You can use the Chain Rule deriving the #()^4# first then the #tan# and finally the argument #3x#: #y'=4tan^3(3x)*(1/(cos^2(3x)))*3=12tan^3(3x)/cos^2(3x)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1746 views around the world You can reuse this answer Creative Commons License