What is the derivative of #sqrt(x^3)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Antoine · Jim H Apr 13, 2015 To solve this problem you can use the chain rule. #f(x)= sqrt(x^3) = (x^3)^(1/2)# #f'(x) = 1/2(x^3)^(-1/2)3x^2 = (3/2x^2)(x^(-3/2)) = 3/2x^(2-3/2) = 3/2x^(1/2) = (3sqrt(x))/2# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1562 views around the world You can reuse this answer Creative Commons License