How do you prove: $cotx-cosx=cotx(1-sinx)$ ?

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Answer 1 · 2015-04-16T09:43:56

Right Hand Side :

$cotx(1-sinx)$

$= cot x - cotx*sinx$ (Distributive Property of Multiplication)

We know that $color(blue)(cot x = cos x / sin x$

$= cot x - (cos x/cancel sin x)*cancel sinx$

$= cot x - cos x$ is the same as the Left hand Side

Hence proved.

How do you prove: cotx-cosx=cotx(1-sinx)cotx-cosx=cotx(1-sinx)?