How do you verify #sinx + cosx cotx = cscx#?

1 Answer
Apr 16, 2015

Left Hand Side :

#sinx + cosx cotx#

We know that #color(blue)(cot x = cos x / sin x #

Therefore #sinx + cosx cotx = sin x + cos x* (cos x/ sinx)#

# = sin x + cos^2 x/sin x #

# = (sin^2x + cos^2x) / sin x#

(We know the Trigonometric Identity
#color(blue)( sin^2x + cos ^ 2 x = 1#)

# = 1 / sinx #

# = csc x# (Because Cosecant is the reciprocal of Sine)

Hence Proved.