Question

How do you simplify `64^(-1/3)`?

Answer 1

Remember
`b^(-a) = 1/(b^a)`
and
`b^(1/c) = root(c)(b)`

therefore
`64^(-1/3)`

`=1/(64^(1/3))`

`=1/(root(3)(64))`

`=1/(root(3)(4^3))`

`=1/4`