How do you graph #y=4sin(2x-pi/2)#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer GiĆ³ Apr 18, 2015 Your function is a sine function with amplitude #4# and starting (at #x=0#) with a value of #-4# (#=4sin(-pi/2)#): Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 8137 views around the world You can reuse this answer Creative Commons License