What does the expression #6[(z^2 +3 (0+2)]# equal with z is -4?

Question

1898 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-22T18:56:58

#6[(z^2+3(0+2)]# when #z=-4#

#= 6[((-4)^2+3(0+2)]#

#= 6[((-4)^2+3*2)]#

#= 6[(16+3*2]#

#= 6[16+6]#

#= 6[22]#

#= 132#