How do you find the range for #y = 1 / (x+5)#?

Question

2419 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-22T20:37:29

#y=1/(x+5)#

Could be written as #y(x+5)=1#

#=>yx+5y=1#

#=>yx=1-5y#

#=>x=(1-5y)/y#

Now, see that the expression on the write can take all values of #y# except #y=0#

Conclusion: our range is #(-oo,0) uu (0, +oo)#

OR simply written as #RR -{0}#