How do you find the derivative of #y = sqrt(2x - x^2)#?

Question

10593 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-29T03:29:33

Write it as:
#y=(2x-x^2)^(1/2)#
and use the Chain Rule to get:
#y'=1/2(2x-x^2)^(1/2-1)*(2-2x)=#
#=(1-x)/sqrt(2x-x^2)#