How do you differentiate #h(x) = (6x-x^3)^2#? Calculus Basic Differentiation Rules Chain Rule 1 Answer GiĆ³ Apr 29, 2015 Have a look: #h'(x)=2(6x-x^3)(6-3x^2)=6x(6-x^2)(2-x^2)# Using the Chain Rule. Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1394 views around the world You can reuse this answer Creative Commons License