How do you solve $4x^2-8=-13x$ by completing the square?

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Answer 1 · 2015-05-02T22:16:47

$y = 4x^2 + 13x - 8 = 0.$

$y = x^2 + (13x)/4 - 2 = 0$
$= x^2 + 13x/4 + 169/16 - 169/16 - 2 = 0$

$(x + 13/8)^2 = 169/64 + 2 = 297/64$

$x = -13/8 + 297/64 =$
$x = -13/8 - 297/64 =$

How do you solve 4x^2-8=-13x4x^2-8=-13x by completing the square?