How do you find the solution of the system of equations # x+3y=12# and #x-3y= -6#?

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Answer 1 · 2015-05-04T07:45:04

Solving by elimination and substitution:

#x+3y = 12#
#x-3y = -6#

on adding the two equations #3y# gets cancelled
#x + cancel(3y) = 12 #
#x - cancel(3y) = -6#

#2x = 6#
# x = 6/2 = 3#

substituting this value of #x# in equation 1:

#x + 3y = 12#
# 3+ 3y = 12#
# 3y = 12 - 3#
#3y = 9#
# y = 3#

the solution for the system of equations are :
#color(blue)x=3#
#color(blue)y=3#