How do you find the solution of the system of equations #x-y=4# and #x-3y= -6#?

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Answer 1 · 2015-05-04T07:57:31

Solving by elimination and substitution:

#x-y = 4#........equation 1

multiplying this equation by '#-1 #' for elimination
#-x + y = -4# ...........equation 1
#x-3y= -6# ..............equation 2

on adding the two equations #x# gets cancelled :
# - 2y = -10# (minus signs cancel)
# y = 10/2# = 5

substituting this value of #y# in equation 1:

#x-y = 4#
#x - 5= 4 #
# x = 9#

the solution for the system of equations are :
#color(blue)x=9#
#color(blue)y=5#