What is the derivative of : #y= e^(1-x)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer GiĆ³ May 6, 2015 I would use the Chain Rule to derive #e# first as it is and then the exponent: #y'=e^(1-x)*(-1)=-e^(1-x)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 1669 views around the world You can reuse this answer Creative Commons License