How do you write the equation of a line in point slope form that is parallel to #y=3x-11# and goes through (9,6)?

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Answer 1 · 2015-05-06T15:53:47

#y=3x-11# is the equation of a line in slope-intercept form.
From this we can deduce that the slope is #m=3#

Any line parallel to #y=3x-11# will also have a slope of #m=3#

Slope-point form of a line is
#(y-y_1) = m(x-x_1)#
and given the point #(x_1,y_1) = (9,6)#

The slope-point form of the required line is
#y-6=3(x-9)#