How do you find the 6 trig functions of 330 degrees?

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Answer 1 · 2015-05-07T16:02:53

Trig unit circle gives:

#sin (330) = sin (360 - 30) = -sin 30 = -1/2# (trig table)

#cos (330) = cos (360 - 30) = cos 30 = (sqr3)/2#(trig table)

#tan (330) = (-1/2)(2/(sqr3)) = -1/(sqr3) = -(sqr3)/3#

#cot (330) = -sqr3#

#sec (330) = 2/(sqr3) = (2.sqr3)/3#

#csc (330) = -2#