How to write an equation in point-slope form, slope-intercept form, & and standard form for a line passing through (-2,-1) and parallel to the line whose equation is #y-2=4/5(x-5)#?
1 Answer
May 7, 2015
The line parallel would have the same slope, hence its point slope form would be y+1=
Solving it for would give the point slope form y=
Simplifying the point slope form would give the standard form 4x-5y= -3