Question

How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: 5π/6?

Answer 1

Given M the extremity of the arc `(5pi)/6`. Its coordinates are:

`y = sin ((5pi)/6) = sin (pi)/6 = 1/2`

`x = cos ((5pi)/6) = - cos pi/6 = -(sqr3)/2`