How do you write the equation of a line in point slope form that is parallel to #y= 1/2x+8# and goes through (2,-7)?

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Answer 1 · 2015-05-11T00:05:31

The given equation #y = 1/2x+8# is in slope-intercept form with a slope of #m=1/2# and a y-intercept of #8#

A line parallel to this will have the same slope (#m=1/2#)

The point-slope form for a line with slope #m# through the point #(x_1,y_1)# is
#(y-y_1) = m(x-x_1)#

or, using the given values
#y+7 = 1/2(x-2)#