How do you simplify #(3 + isqrt2)(3 - isqrt2)#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Nghi N. May 12, 2015 Reminder: i^2 = -1. = (9 - 2i^2) = (9 + 2) = 11 Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1914 views around the world You can reuse this answer Creative Commons License