How do you find the solution of the system of equations #x+3y=12# and #x-y=4#?

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Answer 1 · 2015-05-13T04:49:48

x + 3y = 12 (1)

x - y = 4 (2)

(1) gives x = 12 - 3y. Replace x by (12 - 3y) into (2):

12 - 3y - y = 4 -> -4y = -8 -> y = 2

x = 12 - 3(2) = 6

Check:
(1): 6 + 6 = 12. Correct

(2) : 6 - 3 = 4. Correct