Question

How do you multiply `((a-2)/(a-3)) - 1= 3/(a+2)`?

Answer 1

If you want to find `a`:

`((a-2)(a+2)-1(a-3)(a+2))/cancel((a-3)(a+2))=(3(a-3))/cancel((a-3)(a+2))`

`cancel(a^2)-4cancel(-a^2)-2a+cancel(3a)+6=cancel(3a)-9`

`-2a=-11`

`a=11/2`

Hope it helps!