How do you find the six trigonometric functions of #(5pi)/3# degrees?

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Answer 1 · 2015-05-14T02:18:05

Use the trig unit circle as proof.

#sin ((5pi)/3) = sin (-pi/3 + 2pi) = -sin (pi/3) = (-sqr3)/2#

#cos ((5pi)/3) = cos (-pi/3 + 2pi) = cos (pi/3) = 1/2#

#tan ((5pi)/3) = (-sqr3/2).(2/1) = -sqr3#

#cot ((5pi)/3) = (-sqr3)/3#

#sec ((5pi)/3) = 2#

#csc ((5pi)/3) = ((-2sqr3)/3)#