Question

How do you differentiate `(x-3)/(2x+1)`?

Answer 1

Quocient rule time!

By quocient rule's definition, we have:

`(dy)/(dx) = (f(x))/(g(x)) = (f'(x)*g(x) - f(x)*g'(x))/((f(x))^2)`

Now, let's just proceed:

`(dy)/(dx) = (1*(2x+1) - (x-3)*2)/(x-3)^2` `= (7)/(x^2-6x+9)`

:)