Question

How do you evaluate `cot 30`?

Answer 1

`cot 30 = 1/tan 30`

Trig conversion table gives: `tan 30 = (sqr3)/3`, then

`cot 30 = 3/(sqr3) = (3sqr3)/3 = sqr3`

Answer 2

Assuming your "30" is 30 degrees:

`cot = "adjacent"/"opposite"`

`cot(30^o) = sqrt(3)`