How do you find the derivative of exponential function #y = e^9 ln x#?

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Answer 1 · 2015-05-16T14:20:29

The product rule states that, for a function #y=f(x)g(x)#,

#(dy)/(dx)=f'(x)g(x)+f(x)g'(x)#

So, derivating your function:

#(dy)/(dx)=e^9ln(x)+e^9*(1/x)#

Thus,

#(dy)/(dx)=e^9(ln(x)+(1/x))#