How do you differentiate #tan(cos^3(x))#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bill K. May 18, 2015 Use the Chain Rule: #d/dx(tan(cos^3(x)))=sec^2(cos^3(x))\cdot d/dx(cos^3(x))# #=sec^2(cos^3(x))\cdot 3cos^2(x)\cdot (-sin(x))# #=-3sin(x)cos^2(x)sec^2(cos^3(x))# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1664 views around the world You can reuse this answer Creative Commons License