How do you multiply #(5x+2)/(3x)-(4x-3)/(3x)=( x-1 )/(3x)#?

1 Answer
May 19, 2015

I am not sure if you want to solve it for #x# but I try this:
Take a common denominator on both sides:
#(5x+2-4x+3)/(3x)=(x-1)/(3x)#
(I changed sign in the second numerator on the left);
Now take the #3x# from the denominator (on the left) up to multiply on the right as:
#5x+2-4x+3=(x-1)color(red)(3x)/(3x)# and simplify:
#5x+2-4x+3=(x-1)cancel(color(red)(3x))/cancel((3x))#
You are left with:
#x+5=x-1#
and;
#0=-6# which in not true for any #x#
So your equation has NO SOLUTIONS