Question

Question #31ade

Answer 1

You can add a solution of potassium iodide, `KI`.

The balanced chemical equation for this double replacement reaction would look like this

`Pb(NO_3)_(2(aq)) + 2KI_text((aq]) -> 2KNO_(3(aq)) + PbI_(2(s)) darr`

Lead (II) iodide is a yellow precipitate that will be formed in the reaction.

The ney ionic equation, which you get if the spectator ions are removed, looks like this

`Pb_((aq))^(2+) + 2I_((aq))^(-) -> PbI_(2(s)) darr`

Here's a video of the reaction: