How do you simplify #42 x^11 y^-5#?

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Answer 1 · 2015-05-23T00:54:22

We can use two exponential properties here.

First, #a^-n=1/a^n#.

Now, we have #(42x^11)/y^5#

We also know that #a^n*a^m=a^(n+m)#, so we can rewrite

#(42x^5x^6)/y^5#

Another property indicates that #a^n/b^n=(a/b)^n#, thus, finally,

#(42x^6)(x/y)^5#