Notice that the denominator of each of these terms is a simple multiple of (x+2)(x+2), so we only need to multiply by constants to make the denominators of the two terms the same:
(x+6)/(5x+10)-(x-2)/(4x+8)x+65x+10−x−24x+8
=(x+6)/(5(x+2))-(x-2)/(4(x+2))=x+65(x+2)−x−24(x+2)
=(4*(x+6))/(4*5(x+2))-(5*(x-2))/(5*4(x+2))=4⋅(x+6)4⋅5(x+2)−5⋅(x−2)5⋅4(x+2)
=(4(x+6))/(20(x+2))-(5(x-2))/(20(x+2))=4(x+6)20(x+2)−5(x−2)20(x+2)
=(4(x+6)-5(x-2))/(20(x+2))=4(x+6)−5(x−2)20(x+2)
=(4x+24-5x+10)/(20(x+2))=4x+24−5x+1020(x+2)
=(14-x)/(20(x+2))=14−x20(x+2)
=(14-x)/(20x+40)=14−x20x+40
