How do you write an equation of a line that goes through (-2,7) with m= -4?

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Answer 1 · 2015-05-25T21:01:16

The point-slope equation is #y-7=-4x-8#, and the slope-intercept form is #y=-4x-1#.

Use the point-slope form: #y-y_1=m(x-x_1)#, where #m# is the slope and #x_1# and #y_1# are the known point.

Slope=#-4#;
Point=#(-2,7)#; #x_1=-2#; #y_1=7#

Substitute the known values into the equation.

#y-y_1=m(x-x_1)# =

#y-7=-4(x-(-2)# =

#y-7=-4(x+2)# =

#y-7=-4x-8#

You can convert this into slope-intercept form, #y=mx+b#, by solving for #y#.

#y-7=-4x-8#

Add #7# to both sides.

#y=-4x-1#