How do you use factoring to solve this equation $3x^2-12x=-12$ ?

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Answer 1 · 2015-05-27T00:44:32

Rewrite $3x^2-12x = -12$
as
$3x^2-12x+12 = 0$

Factor out the constant $3$
$3(x^2-4x+4) = 0$

Factor the expression
$3(x-2)(x-2) = 0$

This can only be true if $(x-2) = 0$

Therefore $x=2$

How do you use factoring to solve this equation 3x^2-12x=-123x^2-12x=-12?