Question

How do you simplify `11^(1/2) * 11^(7/3) *11^(1/6)`?

Answer 1

In general `b^p*b^q+b^r = b^(p+q+r)`

So
`11^(1/2)*11^(7/3)*11^(1/6)`

`= 11 ^(1/2+7/3+1/6)`

`= 11 ^((3+14+1)/6)`

`= 11^3`

`= 1331`