How do you solve #1/(x+3) + 1/(x-3) = 1/(x^2-9)#?

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Answer 1 · 2015-05-27T03:33:33

#color(blue)(a^2 - b^2 = (a+b)(a-b)#

#(x^2-9) = (x+3)(x-3)#

the expression given is:
#1/(x+3) + 1/(x-3) = 1/(x^2-9)#

#1/(x+3) + 1/(x-3) = 1/((x+3)(x-3)#

#(1.(x-3))/((x+3)(x-3)) + (1.(x+3))/((x-3)(x+3)) = 1/((x+3)(x-3)#

#((x-3)+ (x+3))/((x+3)(x-3)) = 1/((x+3)(x-3))#

#(2x)/cancel(x^2-9) = 1/cancel(x^2-9)#

#2x = 1#

# x =color(blue)( 1/2# is the solution for the expression.