How do you solve #x(x-7) = 12#?

1 Answer
Alan P.
May 27, 2015

Given #x(x-7) = 12#
we can convert the given form into a standard parabolic quadratic and solve using one of several techniques to obtain the solution(s).

#x(x-7) = 12#

#x^2-7x -12 = 0#

For a quadratic in the form
#ax^2+bx+c=0#
we can use the quadratic formula for roots
#x = (-b+-sqrt(b^2-4ac))/(2a)#

In this case
#x = (7+-sqrt(49+48))/2#

#x=( 7+-sqrt(97))/2#

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