Question

How do you find the solution to the quadratic equation `x^2-3x=10`?

Answer 1

`y = x^2 - 3x - 10` = (x - p)(x - q).
Find p and q knowing product (c = -10) and sum (-b = 3). Compose factor pairs of (-10)--> (-2, 5). This sum is 3 = -b. Then the 2 real roots are: -2 and 5.