Question

How do you find the remaining trigonometric ratios if `sec(theta) = -3.5` and `pi/2< theta < pi`?

Answer 1

`sec x = 1/cos x = -3.5 -> cos x = 1/-3.5 = -0.286`

`sin^2 x = 1 - (0.286)^2 = 0.92 -> sin x = 0.96`

`tan x = 0.96/-0.286 = -3.36`

`cot x = 1/ -3.36 = 0.30`

`csc x = 1/(sin x) = 1/0.96 = 1.04`