How do you write $5 + 3 x$ $5+3x$ in standard form?

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Answer 1 · 2015-05-31T06:45:26

$x = - \frac{5}{3}$ $x=-5/3$

$5 + 3 x = 0$ $5+3x=0$

$3 x = - 5$ $3x=-5$

$x = - \frac{5}{3}$ $x=-5/3$

This should be pretty self-explanatory ;)

Answer 2 · 2015-05-31T11:21:26

In standard form $5 + 3 x$ $5+3x$ is $3 x + 5$ $3x+5$ .

The convention is to gather the highest order terms together first followed by the next highest order, down to any constant term.

For example, $2 + 6 x^{2} y^{2} - 3 x^{3}$ $2+6x^2y^2-3x^3$ would be written as:

$6 x^{2} y^{2} - 3 x^{3} + 2$ $6x^2y^2-3x^3+2$

The order of the first term is $2 + 2 = 4$ $2+2 = 4$ , the next $3$ $3$ and the order of the constant term is $0$ $0$ .

How do you write 5+3x5+3x5+3x in standard form?