How do you find all the asymptotes for function #f(x) = (x+1) / (x+2)#?

1 Answer
May 31, 2015

Let's start with the vertical , the value that is "forbidden" for #x#

Clearly that must be #x=-2# as this would make the denominator #=0# and that is not allowed.

The horizontal is when #x# becomes very large (either negative or positive). You will see that in that case the #+1# and #+2# will have a smaller and smaller effect on the outcome. So the whole thing tends to resemble

#x/x~~1# more and more, or: #lim_(x->+-oo) (x+1)/(x+2)=1#

So #y=1# is the horizontal asymptote:
graph{(x+1)/(x+2) [-10, 10, -5, 5]}