Question

How do you solve `2x^2 - 2x = 1`?

Answer 1

`y = 2x^2 - 2x - 1 = 0`

`D = d^2 = b^2 - 4ac = 4 + 8 = 12 --> d = 2sqrt3`

`x = -b/(2a) +- d/(2a) = 1/2 +- (sqrt3)/2`