Question

How do you write an equation in standard form for a line with y- intercept of 3/2 and slope of m = 1/2?

Answer 1

In slope-intercept form, a line with y-intercept of `3/2` and a slope of `m=1/2` would be written as
`color(white)("XXXXX")` `y=1/2x+3/2`

Standard form is (normally)
`color(white)("XXXXX")` `Ax+By=C` where `A>=0 and AepsilonZZ`

Converting to standard form.
Multiply everything by 2 to clear the fractions
`color(white)("XXXXX")` `2y=1x+3`
Subtract `2y+3` from both sides (and flip the sides)
`color(white)("XXXXX")` `1x-2y = -3`
`color(white)("XXXXX")` `color(white)("XXXXX")`which is in standard form