How do you divide #(5x-5)/16div(x-1)/6#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Tessalsifi Jun 3, 2015 Dividing by #a/b# is the same as multiplying by #b/a# Thus : #=(6*(5x-5))/(16*(x-1))# #=(6*5*(x-1))/(16*(x-1))# ( because #5*(x-1)=5x-5# ) #=(30*(x-1))/(16*(x-1))# #=30/16# ( we divide by #x-1# on each side ) # = 15/8# ( we symplify by dividing by 2 both numerator and denominator ) Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1545 views around the world You can reuse this answer Creative Commons License