How do you find the domain, identify any horizontal, vertical, and slant (if possible) asymptotes and identify holes, x-intercepts, and y-intercepts for #(x^2-25)/(x^2+5x)#?

1 Answer
Jun 4, 2015

I'll give you only a partial answer:

The function can be rewritten as:

#=((x-5)(x+5))/(x*(x+5))#

We can cancel out the #(x+5)#'s
BUT this we only do if #x!=-5#
Also #x!=0#
(both cases will make the numerator #=0#)
So #x=0andx=-5#are points of interest.

The function turns into:
#=(x-5)/x#

That (if #x# gets large enough) will converge to #x/x=1#
graph{(x^2-25)/(x^2+5x) [-22.82, 22.81, -11.4, 11.42]}