How do you solve #-x/2 +1/2x = -4/x#?

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Answer 1 · 2015-06-05T23:01:38

There is no solution to this problem.

Problem: Solve #-x/2+1/2x=-4/x#

Rewrite the equation as:

#-x/2+x/2=-4/x#

Simplify #-x/2+x/2# to #0#.

#0=-4/x#

Multiply both sides by #x#.

#0=-4#

Since #0=-4# is false; there is no solution.